This topic contains 1 reply, has 2 voices, and was last updated by 
Anh Tran 1 year, 10 months ago.
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Topic
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Hello,
If I enter blank a input when I add a variable, it’s get the error.
PHP part: http://prntscr.com/hjkwai
Error: http://prntscr.com/hjkxeqIf I enter a data, the error will fix.
Can you help me?
Kind regards.
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Replies
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Hi,
Looks like you’re using cloneable groups. For each value of a group, please check the existence of sub-fields, like this:
$title = isset( $item_item_item['title'] ) ? $item_item_item['title'] : ''; echo $title;
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